20x/x^2=40

Solution for 20x/x^2=40 equation:

20x/x^2=40

We move all terms to the left:

20x/x^2-(40)=0


Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


20x-40*x^2=0

We add all the numbers together, and all the variables

-40x^2+20x=0

a = -40; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-40)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-40}=\frac{-40}{-80}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-40}=\frac{0}{-80}
=0
$